Question Detail
Answer: Option A Show
Explanation: \begin{aligned} So Compound interest will be 35123.20 - 25000 Similar Questions : 1. The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is
Answer: Option A Explanation: As per question we need something like following \begin{aligned} \end{aligned} So answer is 4 years 2. The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Rs 1. Find the sum
Answer: Option B Explanation: Let the Sum be P C.I. = P(1+\frac{4}{100})^2 - P \\ = \frac{676P}{625} - P \\ 3. On a sum of money, simple interest for 2 years is Rs 660 and compound interest is Rs 696.30, the rate of interest being the same in both cases.
Answer: Option D Explanation: Difference between C.I and S.I for 2 years = 36.30 So R% = \frac{100*36.30}{330*1} = 11% 4. At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years
Answer: Option D Explanation: Let Rate will be R% \begin{aligned} (1+\frac{R}{100})^2 = \frac{134832}{120000} \\ (1+\frac{R}{100})^2 = \frac{11236}{10000} \\ (1+\frac{R}{100}) = \frac{106}{100} \\ 5. Find compound interest on Rs. 7500 at 4% per annum for 2 years, compounded annually
Answer: Option D Explanation: Please apply the formula \begin{aligned} Read more from - Compound Interest Questions Answers P = Rs 25000, n = 3 years, r = 12% p.a \(\therefore\) Amount = P\(\Big(1+\frac{r}{100}\Big)^n\) = Rs 25000 x\(\Big(1+\frac{12}{100}\Big)^3\) = Rs 25000 x \(\Big(\frac{112}{100}\Big)^3\) = Rs 25000 x \(\frac{28}{25}\times\frac{28}{25}\times\frac{28}{25}\) = RS 35123.20 \(\therefore\) Compound interest = Rs (35123.20 – 25000) = Rs 10123.20 A. Rs. 9000.30 B. Rs. 9720 C. Rs. 10123.20 D. Rs. 10483.20 E. None of these Solution(By Examveda Team)$$\eqalign{ & {\text{Amount}} = Rs.\,\left[ {25000 \times {{\left( {1 + \frac{{12}}{{100}}} \right)}^3}} \right] \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,\left( {25000 \times \frac{{28}}{{25}} \times \frac{{28}}{{25}} \times \frac{{28}}{{25}}} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,35123.20 \cr & \therefore {\text{C}}{\text{.I}}{\text{.}} = Rs.\left( {35123.20 - 25000} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = Rs.\,10123.20 \cr} $$ What will be the compound interest on 25000 after 3 years at 12 per annum?(1+12100)3=25000(2825×2825×2825)=35123.20.
What would be the compound interest on a principal of Rs 10000 interest rate 12% for 3 years assuming interest is compounded every month?1,664. ∴ The compound interest is Rs. 1,664.
What will be the amount on Rs 25000 at the rate of 30% per annum compounded yearly for 2 years?Solution : Amount`=P(1+r/100)^t`<br> Amount`=25000(1+4/100)^1`<br> After 2 years <br> Amount`=25000(1+4/100)(1+5/100)`<br> `A=27300`<br> option c is correct.
What is the compound interest of 10000 for 3 years?=13310–10000=₹ 3310.
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What is the compound interest on a principal of 25000 after 3 years at the rate of 12% per annum?
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