The compound interest on a sum of Rs. 20,000 at 15% p.a. for \(2 \frac{2}{3}\)years, when interest compounded yearly is:
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SSC CGL Tier 2 Quant Previous Paper 2 (Held On: 16 November 2020)
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- Rs. 9,000
- Rs. 9,095
- Rs. 9,908
- Rs. 8,896
Answer (Detailed Solution Below)
Option 2 : Rs. 9,095
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CT : General Intelligence and Reasoning (Practice Set)
10 Questions 20 Marks 8 Mins
Given:
Principal = Rs. 20000, Rate = 15%, Time = \(2\frac{2}{{3\;}}\;{\rm{years}}\)
Formula used:
Amount = Principal(1 + rate/100)time
Calculation:
Amount = Principal(1 + rate/100)time
\(\Rightarrow 20000 \times {\left( {1 + \;\frac{{15}}{{100}}} \right)^2}\left( {1 + \;\frac{{\frac{2}{3} \times 15}}{{100}}} \right)\)
\(\Rightarrow 20000 \times {\left( {\;\frac{{23}}{{20}}} \right)^2}\left( {\;\frac{{11}}{{10}}} \right)\)
⇒ 5 × 23 × 23 × 11
⇒ 29095
Interest = Amount – Principal
⇒ 29095 – 20000
⇒ 9095
∴ The compound interest is Rs. 9095.
Last updated on Nov 16, 2022
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Standard VIII
Mathematics
Solving Equations with Variables on Both Sides
In what time ...
Question
A
12 years
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B
8 years
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C
10 years
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D
14 years
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Solution
The correct option is C
10 years
Let the Principal be x
SI = P×R×T100
= x×7.5×T100
⇒ 34x = x×7.5×T100
Cancelling x on both sides of the equation we get,
T = 3×1007.5×4
⇒ T = 10 years
Solving Equations with Variables on Both Sides
Standard VIII Mathematics
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