Multiple Choice Questions
47.
The compound interest on ₹ 5,000 for 3 years at 10% p.a. will amount to
₹ 1,654
₹ 1,655
₹ 1,600
₹ 1,600
B.
₹ 1,655
Compound interest for 3 years is given
by:
⟹ (500 + 550 + 605) = ₹ 1655
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45.
If a boy walks from his house to school at the rate of 4 km per hour, he reaches the school 10 minutes earlier than the scheduled time. However, if he walks at the rate of 3 km per hour, he reaches 10 minutes late. Find the distance of his school from his house.
5 km
4 km
6 km
6 km
B.
4 km
Let the distance of a school be x km,
then
Shortcut Method:
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44.
The distance between A and B is 999 km. An express train leaves place A at 6am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hour 20 minutes. It reaches B at
1.20 am
12 pm
6 pm
6 pm
A.
1.20 am
Distance = 999 km
Speed = 55.5 km/hr
Time taken to cover 999 km =
Train stops = 1 hour 20 minutes
∴ Required time = 18 hours + 1 hour 20 minutes
= 19 hours 20 minutes
i.e. 1 : 20 am.
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49.
A sum of ₹ 3,200 invested at 10% p.a. compounded quarterly amounts to ₹ 3,362. Compute the time period.
-
1 year
2 years
2 years
A.
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D.
21%
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43.
A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time, the ratio of the speed of the jogger to that of the cyclist is
1 : 4
4 : 1
1 : 2
1 : 2
A.
1 : 4
Let the speed of cyclist be x kmph ...(i)
and its time to cover a distance be y
hours.
= (x) X (y) km
Distance covered by cyclist is xy km
Distance
covered by jogger = (xy /2) km
Time = 2y
hours
From (i) and (ii)
Ratio of their speeds =
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46.
Two trains are running 40 km/hr and 20 km/hr respectively in the same direction. The fast train completely passes a man sitting in the slow train in 5 seconds. The length of the fast train is
C.
As trains are moving in the same direction:
Relative speed = 40 - 20 = 20 km/hr
Time = 5 seconds
∴ Length of the faster train
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48.
What sum will give ₹ 244 as the difference between simple interest and compound interest at 10% in
₹ 40,000
₹ 36,000
₹ 32,000
₹ 32,000
C.
₹ 32,000
Shortcut Method:
As interest is compounded
half-yearly. then,
Time (n) =
Rate =
Difference
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42.
Three sets of 40, 50 and 60 studens appeared for an examination and the pass percentage was 100, 90 and 80 respectively. The pass percentage of the whole set is
A.
Required
percentage:
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41.
In an examination A got 25% marks more than B, B got 10% less than C and C got 25% more than D. If D got 320 marks out of 500, the marks obtained by A were
405
450
360
360
B.
450
Marks obtained by D = 320 marks
C got 25% more than D,
∴ Marks obtained by C =
B got 10% less than C
∴ Marks obtained by B = (400 - 10% of 400) = (400 - 40) = ₹ 360
A got 25% more than B:
∴ Marks obtained by A =
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